Correct answer: Qb11...Bb1[a] 2.Q:b1#[A]/B:b1#[Б] 1.Qd4? (2.Q:e4#) 1...Bb1[a] 2.B:b1#[Б]/Qg4#[F] 1...Bg2/[б]//Bh1/[б]//Bc2[e]/Bd5 2.Qg4#[F]
