Correct answer: Rd51...Bb3[a] 2.Q:f1#[A] 1...f2/[б]/ 2.Bd5#[Б] 1...N:c3[c]/Nc7[d]/Nd4[e]/Nd6[d]/Na3[d]/Na7[d] 2.Nd6#[C] 1...Bc2/Bd1 2.Q:b5# 1...b:a5 2.