Correct answer: Rh41...b4 2.Bc6#[A]/Qc6# 1...Rh7/Rh6/Rh5/Rh4/Rh3 2.Bc5# 1.Bc6[A]? (2.Rg4#) 1...Rg8[a] 2.Rh4#[Б] 1...Rh4 2.Bc5#/R
