Correct answer: Nh51.Be3?? (2.Nf6#/Nc3#) but 1...Bc4! 1.Nh5! (2.Ng3#/Nhf6#/Ndf6#/Nc3#) 1...Bg2 2.Nhf6#/Ndf6# 1...Bc4 2.Ng3#/Nf6#