Correct answer: Bd31...Bc3[a] 2.Qe7#[C] 1...B:f6/Bc7/Qd4/[б]//Qd3/Qg8/Qc4[c]/Q:b3 2.Qc7#[Б] 1...Nc4 2.b4# 1...Rc1/Rb1/Ra1 2.Q:d5#[A] 1...
