Correct answer: Qc31...Rf4[a]/Rf3/Rf2/Rf1 2.Ne7#[A] 1...Rf6 2.N:f6#[Б]/Ne7#[A] 1...Rg5/R:h5 2.Nf6#[Б] 1.R:f5? (2.Nf6#[Б]/Ne7#[A]) 1...N