Correct answer: Bg51...Ke5[a] 2.Qe3#[A] 1...Kc5/[б]/ 2.Qc3#[Б] 1...Ne3[c] 2.Qb2#[C] 1.Qf2+? 1...Ke5[a] 2.Qe3#[A] 1...Ne3[c] 2.Qb2#[C] but 1...Kc3
