Correct answer: Rd81...e:d5[a] 2.Qf4#[A] 1...e5/[б]/ 2.Qd2#[Б] 1...Nc4 2.Nab3# 1.d:e6[C]? (2.Rd8#[D]) 1...Nc4 2.Nab3#/Nc6# but 1...R:e6! 1.Rd8[D]! (2.d:e
