Correct answer: Ke51...Q:c3[a] 2.Rf4#[Б] 1...Be2/Qc1/Qf2/Qg2/Qh2/[б]/ 2.Rd4#[A]/Rf4#[Б] 1...Qd2 2.R:d2# 1...Qb1 2.Rd4#[A]/Rf4#[Б]/Rd2#
