Correct answer: Nc51...K:f6[a] 2.Bd4#[A] 1...K:d6/[б]/ 2.Bc7#[Б] 1.Kh4?? zz 1...K:d6/[б]/ 2.Bc7#[Б] but 1...K:f6[a]! 1.Kg4?? zz 1...K:d6/[б]/ 2.Bc7#[