Correct answer: Nc31...Ne3[a]/Nf2/[б]//Nc3/Nb2/[б]/ 2.Bc3#[Б] 1...Kf6/d5[c] 2.Qh8#[A] 1...e6 2.Nd7# 1.Ba3? zz 1...Ne3[a]/Nf2/[б]//Nb2/[б]/ 2.Bb2#