Correct answer: Bd11...d:e4[a] 2.Q:a1#[A] 1...K:e4 2.Bd1# 1...Q:e4 2.h8Q#/h8B# 1.Bd3? (2.Nf7#) 1...d:e4[a] 2.Q:a1#[A] 1...f3/[б]/ 2.Qg3#[C] 1...Q:g1/