Correct answer: Bf21.Bb3[A]? (2.Bf2#[Б]) 1...Re3[a] 2.Rh8#/Bb6#/Bc5#/Bd4#/B:e3#[C]/Bb8# 1...Rf1/R:b3/Re2/Rd2/Rc2/Rb2 2.Rh8#
