Correct answer: Nb71.Nf6[A]? zz 1...b4/[б]/ 2.Nb7#[D] 1...K:e5[c] 2.Nde8#[Б] 1...K:c5[d] 2.Qa7#[C] but 1...f:e4[a]! 1.Nb6[E]? zz 1...K:c5[d]/f:e4[a] 2.Nb7#[D]
