Correct answer: Bc11...K:b4[a] 2.Qb2#[A] 1...a3 2.Qb3# 1.B:e4[Б]? (2.Qa3#[C]) 1...K:b4[a] 2.Qb2#[A] 1...Q:b4/[б]/ 2.Bc1#[D] 1...a3 2.Qb3# but 1...Qd5
