Correct answer: Bc21...Bg7[a] 2.Qf4#[A] 1...e5/[б]/ 2.Qh6#[Б] 1...Ke5 2.Bb2# 1.Bd6? (2.Qh6#[Б]) 1...Bg7[a] 2.Qf4#[A] but 1...Kg7! 1.Bf8? (2.Qf4#[