Correct answer: Kb71...Ne2[a]/Nf3[a]/Nf5[a]/Nc2[a]/Nc6/[б]//Nb3[a]/Nb5[a] 2.Nb5#[A] 1...Ng4[c]/Ng8[c]/Nh5[c]/Nh7[c]/Ne4[c]/Nd5[c] 2.N:e8#[Б]
