Correct answer: Qb31...Nf3[a]/f3[d] 2.Qf5#[Б] 1...Ng2/[б]//Nc2/[б]/ 2.d3#[C] 1...Nd3[c] 2.f3#[D] 1...d3[e] 2.Nac3#[E] 1...Nd8/Ne5/Ne7/Nb4/Nb8/Na5/Na7 2
