Correct answer: Bc31...Rd2[a]/R:d1[a] 2.Qc5#[A] 1...Rd4/[б]/ 2.Qe6#[Б] 1...c6 2.Rd6#/Be6# 1...Bc3 2.N:c3# 1...Be5 2.Be4# 1...Q:b4 2.N:b4# 1.R