Correct answer: Qc71...Ne2[a]/N:f3[a]/N:c2[a]/Nb3[a] 2.R:e6#[A] 1...Nc6/[б]/ 2.Re1#[Б] 1...Bb8 2.Q:d4# 1.R:e6+[A]?? 1...Kd5 2.R:d4#/Bb3# but 1.