Correct answer: Be61...R:d6[a] 2.Qg5#[A] 1...c4/[б]/ 2.Re2#[Б] 1...N:d6[c] 2.Qg7#[C] 1...B:d5[d] 2.Nd3#[D] 1.Bc6? (2.Nd3#[D]/Re2#[Б]) 1...R:d6[a] 2.Re
