Correct answer: Qd71...K:c4[a] 2.Q:c2#[A] 1...b3/[б]/ 2.Nd5#[Б] 1...Ng4/Nh1/Nh3/Nd1/Nd3+ 2.Qd3# 1.Rc7?? zz 1...K:c4[a] 2.Q:c2#[A] 1...b3/[б]/ 2.