Correct answer: Ne51...Bh4[a]/Bh6[a]/B:f6[a] 2.Nd3#[A] 1...e:f2/[б]/ 2.Rf3#[Б] 1...Qa4/Qa3/Qa6/Qb4/Qb6/Qd8 2.Be5#/Q:g5# 1...Qe5 2.B:e5# 1