Correct answer: Bh41...Q:c2[a] 2.N:d7#[Б] 1...Nf6/Qc4/[б]/ 2.Nd3#[A] 1.Kh6? (2.Nd3#[A]/N:d7#[Б]) 1...Q:c2[a] 2.N:d7#[Б] 1...Nf6/Nf8/Nb8/Q