Correct answer: Qf61...Bg2+[a] 2.Q:g2#[A] 1...Be2+/[б]/ 2.Q:e2#[Б] 1...e5 2.c8Q#/c8B# 1...Bh1 2.Rg3# 1...Bd1 2.Rg3#/Qg2#[A] 1.Qd4? (2.Nf6#) 1
