Correct answer: Qd41...b2[a] 2.Qd1#[A] 1...Na5 2.Bb5# 1...Qa2/Q:a1 2.Nc2# 1.Qe4? (2.Qe8#/Qc6#) 1...b2[a] 2.Qc2#[Б] 1...Nd6/[б]//Nd8[c] 2.Qa8
