Correct answer: Qb81...Nd3[a]/Nd7[a]/Ne4[a]/Ne6[a]/Nb3[a]/Nb7/[б]//Na6[d] 2.Q:b5#[A] 1...N:a4[c] 2.Nc4#[Б] 1...b:a4[e] 2.Q:c5#[C] 1...K:b6 2.Qc7# 1.
