Correct answer: Nd11...Nc2[a] 2.Q:c2#[A] 1...a2/[б]/ 2.Qb4#[Б] 1...Nf4/Ng1/Ng3/Nd4/Nc1/Nc3 2.Nd4# 1.Kb5? zz 1...Nc2[a] 2.Q:c2#[A] 1...a2/[б]