Correct answer: Qd61...d3[a] 2.Be3#[A] 1...Bd6/[б]/ 2.Q:d6#[Б]/B:d6#[C] 1...g4 2.Qh6# 1...Bc7 2.Q:c7# 1...Bb8 2.Q:b8# 1.Bd6[C]? zz 1...d3[a] 2.Qe3#[E]
