Correct answer: Bb51...Nc6[a] 2.Bc4#[A] 1...Qc6 2.Rd1# 1...N:e6 2.Ne7# 1...Ne5 2.Nf4# 1.Rc7? (2.Bc4#[A]/Nc3#[Б]) 1...Nc6[a] 2.R:d7# 1...
