Correct answer: Qh21...Kg5[a] 2.Ng2#[A] 1...K:e5/[б]/ 2.f4#[Б] 1...f:e5[c] 2.Ne2#[C] 1.Be7? zz 1...Kg5[a] 2.Ng2#[A] 1...K:e5/[б]/ 2.Bd6#/Qd6#/f4#[Б] 1...f:e