Correct answer: Bf41...Ng1[a]/Nh2/[б]//Ne1[a]/Nd2[a]/Nd4[a] 2.N:h4#[A] 1...Ne3[c]/Ne7[c]/Nf4/Nf6[d]/Nc3[c]/Nb4[c]/Nb6[c] 2.N:e3#[C] 1...N:e5
