Correct answer: Qb71...Kf3[a]/Rd5 2.Ng5#[A] 1...Kd5/[б]/ 2.Nf6#[Б] 1.Nb4? (2.Ng5#[A]/Bg2#[C]) 1...Kf3[a]/Rd3 2.Ng5#[A] 1...Be7 2.Bg2#[C]
