Correct answer: d41...Bc5[a]/Ba5[a] 2.Q:c5#[A] 1...Bd4/[б]/ 2.Qe4#[Б] 1...Rb4[c] 2.N:b4#[C] 1...Rd4[d] 2.Ne3#[D] 1...Ne6/Nf7/Nb7 2.Q:e6# 1...R