Correct answer: Ne31...Ng2[a]/Nd3[a]/Nc2 2.Rd3#[A] 1...Bd5/[б]/ 2.Nb5#[Б] 1...Bc4[c] 2.Nc6#[C] 1...d5 2.Nb5#[Б]/Qc5# 1...Be6 2.Bg7# 1...Be3/Bb
