Correct answer: Q:c21...c:b2[a] 2.Qd2#[A] 1...Ba2/[б]/ 2.N:c2#[Б] 1...e3[c] 2.Nf3#[C] 1...g:h2[d] 2.Qe3#[D] 1.Qf4? (2.Nf3#[C]/Q:e4#[E]) 1...c:b2[a] 2.Qd2#[A] 1...c1
