Correct answer: Rd81.Rb8? zz 1...Kc2/[б]/ 2.Qb1#[A] 1...Kc4[c] 2.Qd4#[Б] but 1...Ke4[a]! 1.Be6[C]? (2.Qb1#[A]) 1...Ke4[a] 2.Qe3# but 1...Kc2/[б]/!
