Correct answer: Nd21...e4[a] 2.Qf6#[A] 1...Nf5/[б]//Ng6[c]/Ng8[c]/Nd5[d]/N:c6[c]/Nc8[c] 2.Qd5#[Б] 1...Nb1[e]/Nb5[e]/Nc2[e]/Nc4[e] 2.Qc4#[C] 1...Ke
