Correct answer: Qd61...K:a7[a] 2.Qa5#[A] 1...B:a7/[б]/ 2.Qg2#[Б] 1.Qf4? (2.Qb8#) 1...K:a7[a] 2.Qa4#[C] 1...B:a7/[б]/ 2.Qe4#[D] but 1...e5! 1.Qd5+??
