Correct answer: Ne31...e1Q[a]/e1R[a]/e1B 2.Rd3#[A] 1...e1N/[б]/ 2.Rf2#[Б] 1...Ke1 2.Bc3# 1.Rcc3? zz 1...e1Q[a]/e1R[a]/e1B 2.Rfd3#[C] 1...e1<
