Correct answer: Qb71.d3? zz 1...Bc3[a]/Ba3 2.Nb3#[C] 1...B:c1/[б]/ 2.R:c1#[Б] but 1...Kb1! 1.Qd5? zz 1...Bc3[a] 2.Nd3#[D] 1...B:c1/[б]/ 2.B:d4#[A]
