Correct answer: Qa11...Be6 2.Bc6# 1.Q:f2? (2.Rb5#) 1...B:d7/[б]//N:d7 2.Qa2#[A] 1...N:d3[c] 2.Q:f3#[Б] 1...N:d4 2.Q:d4# but 1...B:d3[a]! 1.
