Correct answer: Qg41...K:g2[a] 2.Qc2#[A] 1...h:g2/[б]/ 2.Qh8#[Б] 1.Qc7? zz 1...K:g2[a] 2.Qc2#[A] 1...h:g2/[б]/ 2.Qh7#[C] but 1...g4! 1.Qc6? zz 1...K:g2[a] 2.<
