Correct answer: Qh81...e3[a] 2.Qc6# 1...Ke3 2.Qc3# 1.Qe5? zz 1...e3[a] 2.Qd5#[A] 1...Bf1[c]/Bd1[d]/Bc4[f]/Bb5[f]/Ba6[f] 2.Q:e4#[D]/Qh5#[C] 1...<
