Correct answer: Kf11...Ng4[a]/Nh1[a]/Nh3[a]/Nd1[a] 2.Q:d3#[C] 1...b4/[б]/ 2.Re5#[D] 1...Kd5 2.Qc4#[A] 1...b6 2.Qc6#[Б] 1.R:a6? zz 1...Ng4[a]/Nh1[a]/