Correct answer: Ng71...e6[a] 2.Nf6#[A] 1...d:c5/[б]/ 2.N:e5#[Б] 1...Na6 2.c6# 1.Nd4? (2.Nf6#[A]/N:e5#[Б]) 1...e6[a] 2.Rd8#[D] 1...d:c5/[б]/ 2.Qd5#[C] 1...f5 2.Qe6#
