Correct answer: Bb61...Ke6[a] 2.R:d6#[A]/Bc4#[Б]/R:e5#[C] 1...d:c5 2.R:e5#[C]/Rd6#[A] 1.Kb7? (2.Bc4#[Б]) 1...Ke6[a] 2.R:d6#[A] but 1...a:b5! 1.Qh1? (2.