Correct answer: Qc81...N:f4[a]/Ng1[a]/Ng3[a]/N:d4/[б]//Nc1[a] 2.Ng3#[A] 1...e6[c]/e5[c] 2.Nd6#[C] 1...Nc3 2.Nc5#/Ng3#[A] 1...Rc1/Rc3/Rc4/Rc6/R<