Correct answer: Nc51.Nf4? (2.Ne2#[A]/Nd3#[Б]) 1...Rb3/Rd8/Nb4 2.Ne2#[A] 1...Nc3 2.Nd3#[Б] but 1...Bb5! 1.Nd4? (2.Ne2#[A]) 1...Bb5 2.N<