Correct answer: Bg41...Kf4[a]/f6[c] 2.Nd3#[A] 1...Kf6/[б]/ 2.Ng4#[Б] 1.Kg5? (2.Ng4#[Б]/Nd3#[A]) but 1...f6+[c]! 1.B:f3[C]? zz 1...Kf6/[б]/ 2.Ng4#[Б] 1...f6[
